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A062210
Numbers k such that the smoothly undulating palindromic number (14*10^k - 41)/99 is a prime.
1
11, 277, 479, 583, 1631, 6343, 14689
OFFSET
1,1
COMMENTS
Prime versus probable prime status and proofs are given in the author's table.
No further terms < 100000. - Ray Chandler, Aug 17 2011
EXAMPLE
11 is in the sequence because (14*10^11 - 41)/99 = 14141414141 is prime.
CROSSREFS
KEYWORD
nonn,base,more
AUTHOR
Patrick De Geest and Hans Rosenthal (Hans.Rosenthal(AT)t-online.de), Jun 15 2001
EXTENSIONS
Edited by Ray Chandler, Aug 17 2011
Name and Example edited by Jon E. Schoenfield, Jun 25 2017
STATUS
approved