%I
%S 11,277,479,583,1631,6343,14689
%N Numbers k such that the smoothly undulating palindromic number (14*10^k  41)/99 is a prime.
%C Prime versus probable prime status and proofs are given in the author's table.
%C No further terms < 100000.  _Ray Chandler_, Aug 17 2011
%H P. De Geest, <a href="http://www.worldofnumbers.com/undulat.htm#supp141">SUPP Reference Table  141</a>
%H <a href="/index/Pri#pri_supp">Index entries for sequences related to smoothly undulating palindromic primes</a>
%e 11 is in the sequence because (14*10^11  41)/99 = 14141414141 is prime.
%Y Cf. A062209A062232, A059758, A032758.
%K nonn,base,more
%O 1,1
%A _Patrick De Geest_ and Hans Rosenthal (Hans.Rosenthal(AT)tonline.de), Jun 15 2001
%E Edited by _Ray Chandler_, Aug 17 2011
%E Name and Example edited by _Jon E. Schoenfield_, Jun 25 2017
