OFFSET
1,1
COMMENTS
a(n) <= Fibonacci(6n) since 4 | Fibonacci(6n). Using other residue classes it can be shown that a(n) << 1.134^n. How far can this method be taken? - Charles R Greathouse IV, Dec 13 2011
LINKS
Amiram Eldar, Table of n, a(n) for n = 1..328 (terms 1..87 from Harry J. Smith)
FORMULA
EXAMPLE
144 and 2584 are Fibonacci numbers (A000045) and are not squarefree: 144 = 2^4*3^2, 2584 = 2^3*17*19.
MATHEMATICA
Select[Fibonacci[Range[100]], !SquareFreeQ[#]&] (* Harvey P. Dale, May 01 2018 *)
PROG
(PARI) { n=0; h=g=1; for (i=0, 375, f=g + h; h=g; g=f; if (!issquarefree(f), write("b061899.txt", n++, " ", f)) ) } \\ Harry J. Smith, Jul 28 2009
CROSSREFS
KEYWORD
nonn
AUTHOR
Asher Auel, May 20 2001
STATUS
approved