OFFSET
1,1
FORMULA
For p=2, 24 is the solution. If p>2 prime, then suitable powers of 30 are the least solutions: a(n)=Min{x|d(x)=A000005(x)=p(n)^3}=30^[p(n)-1], p(n)=n-th prime; d[2^(ppp-1)]=d[2^(pp-1)3^(p-1)]=d[30^(p-1)]=p^3 and 2^(ppp-1)>2^(pp-1)3^(p-1)>30^(p-1) holds if p>2.
EXAMPLE
p=2, then d(128)=d(24)=d(30)=8 and a(1)=24<30 is the smallest; P=5, then 2^124>(2^24)*(3^4)>30^4=810000=a(3).
CROSSREFS
KEYWORD
nonn
AUTHOR
Labos Elemer, Jun 01 2001
STATUS
approved