

A061143


a(1) = 1; a(n) = sum of terms in the continued fraction for the square of the continued fraction [a(1); a(2), a(3), a(4),..., a(n1)].


0



1, 1, 4, 13, 82, 121, 218, 278, 498, 305, 358, 510, 666, 828, 939, 1189, 1155, 1335, 1870, 2101, 1770, 16411, 1380, 2082, 14035, 2437, 1734, 3079, 4537, 2335, 3923, 2750, 8259, 3144, 2986, 2803, 6187, 2833, 5008, 3251, 3442, 4588, 3767
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OFFSET

1,3


LINKS



EXAMPLE

(1 +(1/(1 +1/4)))^2 = (9/4)^2 = 81/25 = 3 +1/(4 +1/6). So a(4) = 3 + 4 + 6 = 13.


CROSSREFS



KEYWORD

easy,nonn


AUTHOR



STATUS

approved



