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A061143 a(1) = 1; a(n) = sum of terms in the continued fraction for the square of the continued fraction [a(1); a(2), a(3), a(4),..., a(n-1)]. 0
1, 1, 4, 13, 82, 121, 218, 278, 498, 305, 358, 510, 666, 828, 939, 1189, 1155, 1335, 1870, 2101, 1770, 16411, 1380, 2082, 14035, 2437, 1734, 3079, 4537, 2335, 3923, 2750, 8259, 3144, 2986, 2803, 6187, 2833, 5008, 3251, 3442, 4588, 3767 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,3
LINKS
EXAMPLE
(1 +(1/(1 +1/4)))^2 = (9/4)^2 = 81/25 = 3 +1/(4 +1/6). So a(4) = 3 + 4 + 6 = 13.
CROSSREFS
Sequence in context: A140417 A301396 A221512 * A354152 A354409 A123333
KEYWORD
easy,nonn
AUTHOR
Leroy Quet, May 29 2001
STATUS
approved

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Last modified April 13 11:55 EDT 2024. Contains 371640 sequences. (Running on oeis4.)