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A059989
Numbers k such that 3*k+1 and 4*k+1 are both squares.
4
0, 56, 10920, 2118480, 410974256, 79726887240, 15466605150360, 3000441672282656, 582070217817684960, 112918621814958599640, 21905630561884150645256, 4249579410383710266580080, 824396499983877907565890320, 159928671417461930357516142056, 31025337858487630611450565668600
OFFSET
1,2
FORMULA
a(n) = (A001570(n)^2 - 1)/3.
G.f.: 56*x^2 / (1-195*x+195*x^2-x^3).
From Colin Barker, Mar 03 2016: (Start)
a(n) = 195*a(n-1)-195*a(n-2)+a(n-3) for n > 3.
a(n) = (-1)*((97+56*sqrt(3))^(-n)*(-1+(97+56*sqrt(3))^n)*(7+4*sqrt(3)+(-7+4*sqrt(3))*(97+56*sqrt(3))^n))/48. (End)
Sum_{n>=2} 1/a(n) = (7 - 4*sqrt(3))/4. - Amiram Eldar, Jan 27 2026
EXAMPLE
3*56+1 = 13^2 and 4*56+1 = 15^2.
MAPLE
f:= proc(n) local u;
u:= <<7, 8>|<6, 7>>^n . <1, -1>;
(u[1]^2-1)/3
end proc:
map(f, [$1..30]); # Robert Israel, Mar 03 2016
MATHEMATICA
CoefficientList[Series[56 x/(1 - 195 x + 195 x^2 - x^3), {x, 0, 13}], x] (* Michael De Vlieger, Mar 03 2016 *)
PROG
(PARI) isok(n) = issquare(3*n+1) && issquare(4*n+1) \\ Michel Marcus, Jun 08 2013
(PARI) concat(0, Vec(56*x^2/((1-x)*(1-194*x+x^2)) + O(x^20))) \\ Colin Barker, Mar 03 2016
CROSSREFS
Sequence in context: A034204 A275921 A091546 * A352602 A184125 A213865
KEYWORD
nonn,easy
AUTHOR
David Radcliffe, Mar 07 2001
EXTENSIONS
Offset changed to 1 by Joerg Arndt, Mar 03 2016
STATUS
approved