OFFSET
1,2
COMMENTS
Since 2^0.5 is irrational such m must exist because for any irrational number a the sequence a,2a,3a,4a,5a,... is dense modulo 1.
All terms are contained in A079496. - Ralf Stephan, Sep 09 2004
FORMULA
a(n) = min m such that m*(2^0.5)-floor(m*(2^0.5)) < 2^(-n).
EXAMPLE
a(7) = 99 because 99*(2^0.5) = 140.00714267... and 0.00714267... < 2^(-7) = 0.0078125 and 99 is the least natural number that satisfies this inequality.
PROG
(PARI) o=1:for(n=1, 50, for(m=o, 10^9, if(frac(sqrt(2)*m)<2^(-n), print1(m", "):o=m:break)))
CROSSREFS
KEYWORD
nonn
AUTHOR
Avi Peretz (njk(AT)netvision.net.il), Dec 25 2000
EXTENSIONS
More terms from Ralf Stephan, Mar 27 2003
More terms from Sean A. Irvine, Aug 10 2022
STATUS
approved