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A050427
Numbers for which in base 2 the least number of digits that can be removed to leave a base 2 palindromic number (beginning with 1) is 3.
4
8, 24, 40, 44, 52, 56, 72, 76, 78, 92, 100, 114, 116, 120, 136, 140, 142, 143, 148, 150, 151, 158, 164, 168, 172, 174, 188, 196, 210, 212, 216, 220, 226, 233, 234, 236, 241, 242, 244, 248, 264, 268, 270, 271, 276, 278, 279, 282, 283, 287, 303, 308, 310, 318
OFFSET
1,1
EXAMPLE
(72 base 2) = 1001000 -> 1001.
PROG
(Python)
from itertools import combinations
def ok(n):
b = bin(n)[2:]
for digs_to_remove in range(4):
for skip in combinations(range(len(b)), digs_to_remove):
newb = "".join(b[i] for i in range(len(b)) if i not in skip)
if len(newb) > 0 and newb[0] == '1' and newb == newb[::-1]:
return (digs_to_remove == 3)
return False
print(list(filter(ok, range(320)))) # Michael S. Branicky, Aug 24 2021
CROSSREFS
KEYWORD
nonn,base
STATUS
approved