OFFSET
4,2
FORMULA
Seems to be n * A006918.
From Chai Wah Wu, Jun 11 2016: (Start)
a(n) = 2*a(n-1) + 2*a(n-2) - 6*a(n-3) + 6*a(n-5) - 2*a(n-6) - 2*a(n-7) + a(n-8) for n > 11 (conjectured).
G.f.: x^5*(5 + 2*x + x^2)/((1 - x)^5*(1 + x)^3) (conjectured). (End)
CROSSREFS
KEYWORD
nonn
AUTHOR
STATUS
approved