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A047243
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Numbers that are congruent to {2, 3} mod 6.
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6
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2, 3, 8, 9, 14, 15, 20, 21, 26, 27, 32, 33, 38, 39, 44, 45, 50, 51, 56, 57, 62, 63, 68, 69, 74, 75, 80, 81, 86, 87, 92, 93, 98, 99, 104, 105, 110, 111, 116, 117, 122, 123, 128, 129, 134, 135, 140, 141, 146, 147, 152, 153, 158, 159, 164, 165, 170, 171, 176, 177, 182, 183
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OFFSET
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1,1
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COMMENTS
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Solutions to 3^x - 2^x == 5 (mod 7). - Cino Hilliard, May 09 2003
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REFERENCES
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Emil Grosswald, Topics From the Theory of Numbers, 1966, p. 65, problem 23.
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LINKS
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FORMULA
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G.f.: x*(2+x+3*x^2) / ( (1+x)*(1-x)^2 ). - R. J. Mathar, Oct 08 2011
a(n) = a(n-2) + 6 with a(1)=2, a(2)=3 for n > 2;
a(n) = 3*n - 2 - (-1)^n. (End)
E.g.f.: 3 - 3*(1-x)*cosh(x) - (1-3*x)*sinh(x). - G. C. Greubel, Jun 30 2019
E.g.f.: 3 + (3*x-3)*exp(x) + 2*sinh(x). - David Lovler, Jul 16 2022
Sum_{n>=1} (-1)^(n+1)/a(n) = Pi/(12*sqrt(3)) + log(3)/4 - log(2)/3. - Amiram Eldar, Dec 13 2021
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MATHEMATICA
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Select[Range[0, 210], MemberQ[{2, 3}, Mod[#, 6]] &] (* or *)
Fold[Append[#1, 6 #2 - Last@ #1 - 7] &, {2}, Range[2, 70]] (* or *)
Rest@ CoefficientList[Series[x(2+x+3x^2)/((1+x)(1-x)^2), {x, 0, 70}], x] (* Michael De Vlieger, Jan 12 2018 *)
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PROG
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(Magma) [3*n-2-(-1)^n: n in [1..70]]; // G. C. Greubel, Jun 30 2019
(Sage) [3*n-2-(-1)^n for n in (1..70)] # G. C. Greubel, Jun 30 2019
(GAP) List([1..70], n-> 3*n-2-(-1)^n) # G. C. Greubel, Jun 30 2019
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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