OFFSET
1,2
COMMENTS
The sequence is expected to be infinite. Heuristically, if m is divisible by 10 there should be approximately constant * 10^(m/2)/m^(9/2) m-digit squares where all 10 digits have frequency m/10. - Robert Israel, Aug 14 2015
LINKS
Robert Israel, Table of n, a(n) for n = 1..3000
P. De Geest, Numbers whose digits occur with same frequency
MAPLE
filter:= proc(n) local x, i, P;
P:= add(x^i, i=convert(n^2, base, 10));
nops({coeffs(P, x)}) = 1
end proc:
select(filter, [$1..10^4]); # Robert Israel, Aug 14 2015
MATHEMATICA
t={}; Do[If[Length[DeleteDuplicates[Transpose[Tally[IntegerDigits[n^2]]][[2]]]]==1, AppendTo[t, n]], {n, 136}]; t (* Jayanta Basu, May 10 2013 *)
CROSSREFS
KEYWORD
base,nonn
AUTHOR
STATUS
approved