

A032097


"BHK" (reversible, identity, unlabeled) transform of 2,1,1,1,...


3



2, 2, 5, 14, 39, 107, 289, 772, 2047, 5402, 14213, 37325, 97905, 256622, 672337, 1760998, 4611643, 12075527, 31617521, 82781216, 216732891, 567428402, 1485570025, 3889310329, 10182407329, 26657986682, 69791674109, 182717232062, 478360339887
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OFFSET

1,1


COMMENTS

First five terms match the total dominating number of the nSierpinski sieve graph.  Eric W. Weisstein, Apr 18 2018
From Petros Hadjicostas, May 20 2018: (Start)
Using the formulae in C. B. Bower's web link below about transforms, it can be proved that, for k >= 2, the BHK[k] transform of sequence (c(n): n >= 1), which has g.f. C(x) = Sum_{n >= 1} c(n)*x^n, has generating function B_k(x) = (1/2)*(C(x)^k  C(x^2)^{k/2}) if k is even, and B_k(x) = C(x)*B_{k1}(x) = (C(x)/2)*(C(x)^{k1}  C(x^2)^{(k1)/2}) if k is odd. For k=1, Bower assumes that the BHK[k=1] transform of (c(n): n >= 1) is itself, which means that the g.f. of the output sequence is C(x). (This assumption is not accepted by all mathematicians because a sequence of length 1 not only is reversible but palindromic as well.)
Since BHK(c(n): n >= 1) = Sum_{k=1..n} BHK[k](c(n): n >= 1), it can be easily proved (using sums of infinite geometric series) that the g.f. of BHK(c(n): n >= 1) is A(x) = (C(x)^2  C(x^2))/(2*(1C(x))*(1C(x^2))) + C(x). (The extra C(x) is due of course to the special assumption made for the BHK[k=1] transform.)
For the current sequence, c(1) = 2 and c(n) = 1 for all n >= 2, and thus, C(x) = x + x/(1x). Substituting into the above formula for A(x), and doing the algebra, we get A(x) = x*(x^54*x^4+x^3+9*x^28*x+2)/((x1)*(x^23*x+1)*(x^2+x1)), which is the formula given by Colin Barker below.
(End)


LINKS

Vincenzo Librandi, Table of n, a(n) for n = 1..1000
C. G. Bower, Transforms (2)
Index entries for linear recurrences with constant coefficients, signature (5,7,1,3,1).


FORMULA

For n > 1, a(n) = (1/2)*(F(2n+1)  F(n+2) + 2), where F(n) = A000045(n).  Ralf Stephan, May 04 2004
G.f.: x*(x^54*x^4+x^3+9*x^28*x+2)/((x1)*(x^23*x+1)*(x^2+x1)).  Colin Barker, Sep 22 2012


EXAMPLE

From Petros Hadjicostas, May 20 2018: (Start)
According to C. G. Bower, in his website above, we have boxes of different colors and sizes (the size of the box is determined by the number of balls it can hold). Since c(1) = 2, each box of size 1 can have one of two colors, say A and B. On the other hand, since c(n) = 1 for n >= 2, each box of size >= 2 can be of one color only (and there is no need to specify it). Then a(n) = BHK(c(n): n >= 1)(n) = number of ways we can have boxes on a line such that the total number of balls is n and the array of boxes is reversible but not palindromic (with the exception when having only one box on the line).
Hence, for n=1, the a(1) = 2 possible arrays are 1_A and 1_B. For n=2, the a(2) = 2 possible arrays for the boxes are 1_A 1_B and 2. (Note that 1_A 1_B is not palindromic because the boxes have different colors even though each one has only 1 ball.)
For n=3, the a(3) = 5 possible arrays for the boxes are:
3 (one box on the line);
1_A 2, 1_B 2 (two boxes on the line);
1_A 1_B 1_B, 1_A 1_A 1_B (three boxes on the line).
For n=4, the a(4) = 14 possible arrays for the boxes are:
4 (one box on the line);
1_A 3, 1_B 3 (two boxes on the line);
1_A 1_A 2, 1_A 1_B 2, 1_B 1_A 2, 1_B 1_B 2, 1_A 2 1_B (three boxes on the line);
1_A 1_A 1_A 1_B, 1_A 1_A 1_B 1_A, 1_A 1_A 1_B 1_B, 1_A 1_B 1_B 1_B,
1_B 1_A 1_B 1_B, 1_A 1_B 1_A 1_B (four boxes on the line).
(End)


MATHEMATICA

CoefficientList[Series[(x^5  4 x^4 + x^3 + 9 x^2  8 x + 2)/((x  1) (x^2  3 x + 1) (x^2 + x  1)), {x, 0, 40}], x] (* Vincenzo Librandi, Oct 19 2013 *)
Join[{2}, Table[(Fibonacci[2 n + 1]  Fibonacci[n + 2])/2 + 1, {n, 2, 20}]] (* Eric W. Weisstein, Apr 18 2018 *)
Join[{2}, LinearRecurrence[{5, 7, 1, 3, 1}, {2, 5, 14, 39, 107}, 20]] (* Eric W. Weisstein, Apr 18 2018 *)


PROG

(MAGMA) [2] cat [1/2*(Fibonacci(2*n+1)  Fibonacci(n+2) + 2): n in [2..30]]; // Vincenzo Librandi, Oct 19 2013


CROSSREFS

Sequence in context: A282275 A208201 A185966 * A176856 A112709 A291573
Adjacent sequences: A032094 A032095 A032096 * A032098 A032099 A032100


KEYWORD

nonn,easy


AUTHOR

Christian G. Bower


EXTENSIONS

More terms from Vincenzo Librandi, Oct 19 2013


STATUS

approved



