OFFSET
1,2
COMMENTS
All zeros are counted, not just the trailing zeros. So a particular n! might have more zeros than (n - 1)! (e.g., n = 10), but that's not enough for it to be in the sequence. - Alonso del Arte, Apr 30 2017
LINKS
David A. Corneth, Table of n, a(n) for n = 1..476
EXAMPLE
Since 0! = 1, 0! has no significant zeros, and so 0 is the first term of the sequence.
It isn't until 5! = 120 that n! gets its first significant zero, so 5 is the second term of the sequence.
MATHEMATICA
Function[s, -1 + Map[First@ Position[s, #] &, Union@ FoldList[Max, s]]]@ Array[DigitCount[#!, 10, 0] &, 430, 0] // Flatten (* Michael De Vlieger, May 12 2017 *)
PROG
(PARI) lista(n) = my(l = List([0]), m=0, p=1, d); for(i=2, n, p*=i; d = digits(p); s = sum(i=1, #d, d[i]==0); if(s > m, listput(l, i); m=s)); l \\ David A. Corneth, May 19 2017
CROSSREFS
KEYWORD
nonn,base,easy
AUTHOR
EXTENSIONS
Corrected and extended by Erich Friedman.
Name clarified by Alonso del Arte, Apr 30 2017
Offset changed by N. J. A. Sloane, May 20 2017
STATUS
approved
