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A027808
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a(n) = 55*(n+1)*binomial(n+4,12).
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1
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495, 7150, 55055, 300300, 1301300, 4764760, 15315300, 44341440, 117781950, 290990700, 675745070, 1487285800, 3123300180, 6292363000, 12216990500, 22946695200, 41829913125, 74211187050, 128442439125, 217325608500, 360139579800, 585448578000, 934943638200
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OFFSET
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8,1
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COMMENTS
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Number of 17-subsequences of [ 1, n ] with just 4 contiguous pairs.
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LINKS
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Index entries for linear recurrences with constant coefficients, signature (14,-91,364,-1001,2002,-3003,3432,-3003,2002,-1001,364,-91,14,-1).
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FORMULA
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G.f.: 55*(9+4*x)*x^8/(1-x)^14.
Sum_{n>=8} 1/a(n) = 6*Pi^2 - 631959059/10672200.
Sum_{n>=8} (-1)^n/a(n) = 3*Pi^2 + 77824*log(2)/385 - 1811284381/10672200. (End)
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MATHEMATICA
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Table[55(n+1)Binomial[n+4, 12], {n, 8, 30}] (* or *) CoefficientList[ Series[(55(4x+9))/(x-1)^14, {x, 0, 22}], x] (* Harvey P. Dale, Nov 20 2011 *)
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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