A024573 a(n) = floor(1/frac(n*e)).

1, 2, 6, 1, 1, 3, 35, 1, 2, 5, 1, 1, 2, 17, 1, 2, 4, 1, 1, 2, 11, 1, 1, 4, 1, 1, 2, 8, 1, 1, 3, 1, 1, 2, 7, 1, 1, 3, 76, 1, 2, 5, 1, 1, 3, 24, 1, 2, 5, 1, 1, 2, 14, 1, 1, 4, 1, 1, 2, 10, 1, 1, 3, 1, 1, 2, 8, 1, 1, 3, 1, 1, 2, 6, 1, 1, 3, 38, 1, 2, 5, 1, 1, 2, 18, 1, 2, 4, 1, 1, 2, 12, 1, 1, 4, 1, 1, 2, 9, 1

Offset

1,2

Comments

The sequence is well defined, since frac(n*e)>0 for n>0.

Let b(n,m) = |{a(k)| 1<=k<=n, a(k)>=m}| be the number of the first n terms which are >= m >= 1.

Then, lim b(n,m)/n = 1/m for n-->oo since frac(n*e) is uniformly distributed. - Hieronymus Fischer, Apr 15 2012

Links

Clark Kimberling, Table of n, a(n) for n = 1..1000

Mathematica

f[n_] := Floor[1/FractionalPart[n*E]]; Array[f, 100] (* Robert G. Wilson v, Apr 17 2012 *)

Crossrefs

Cf. A024584, A022843.

Sequence in context: A205015 A204937 A126749 * A191359 A339766 A289203

Adjacent sequences: A024570 A024571 A024572 * A024574 A024575 A024576

Keyword

nonn

Author

Clark Kimberling

Status

approved