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A023651
Numbers k such that (product of digits of k) * (sum of digits of k) = 2k.
4
0, 2, 15, 24, 1575, 39366
OFFSET
1,2
COMMENTS
Except for k = 0, this sequence is a subsequence of A049101. - Jason Yuen, Feb 26 2024
MATHEMATICA
Do[ If[ 2n == Apply[ Times, IntegerDigits[n]] Apply[ Plus, IntegerDigits[n]], Print[n]], {n, 0, 10^7} ]
PROG
(PARI) isok(n) = if(n, factorback(digits(n)), 0) * sumdigits(n) == 2*n \\ Mohammed Yaseen, Jul 22 2022
(Python)
from math import prod
def s(n): return sum(map(int, str(n)))
def p(n): return prod(map(int, str(n)))
for n in range(0, 10**6):
if p(n)*s(n)==2*n:
print(n) # Mohammed Yaseen, Jul 22 2022
CROSSREFS
KEYWORD
nonn,base,fini,full
AUTHOR
Jason Earls, Dec 11 2001
EXTENSIONS
Offset corrected by Arkadiusz Wesolowski, Oct 17 2012
STATUS
approved