OFFSET
0,6
COMMENTS
Generalization:
1/88 = sum (12^i/100^(i+1)), i >= 0,
1/988 = sum (12^i/1000^(i+1)), i >= 0, (this sequence)
1/9988 = sum (12^i/10000^(i+1)), i >= 0, ... - Daniel Forgues, Oct 28 2011
LINKS
Index entries for linear recurrences with constant coefficients, signature (1,0,0,0,0,0,0,0,-1,1).
FORMULA
From Chai Wah Wu, Mar 07 2021: (Start)
a(n) = a(n-1) - a(n-9) + a(n-10) for n > 11.
G.f.: x^2*(-5*x^9 + 3*x^8 - 2*x^7 - x^6 - 3*x^5 + x^4 - x^3 - x^2 + x - 1)/(x^10 - x^9 + x - 1). (End)
CROSSREFS
KEYWORD
nonn,cons
AUTHOR
STATUS
approved