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A020733
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Consider number of prime divisors of C(n,k), k=0..n; a(n) = multiplicity of maximal value.
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3
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2, 1, 2, 1, 2, 5, 4, 1, 4, 2, 4, 1, 2, 5, 8, 1, 2, 5, 8, 2, 6, 7, 8, 5, 8, 11, 2, 2, 4, 11, 10, 3, 8, 2, 6, 3, 6, 2, 4, 1, 2, 5, 8, 2, 12, 16, 16, 5, 6, 13, 8, 12, 12, 4, 8, 5, 4, 5, 6, 4, 2, 6, 10, 1, 2, 7, 6, 5, 2, 2, 12, 15, 16, 2, 8, 11, 2, 10, 10, 11, 2, 6, 12, 3, 16, 2, 4, 8, 10, 5, 2, 2, 4, 6
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OFFSET
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1,1
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LINKS
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EXAMPLE
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The number of distinct primes of C(15,k) are {0,2,3,3,4,4,4,4,4,4,4,4,3,3,2,0}; maximum is 4 and occurs 8 times; thus a(15)=8.
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MAPLE
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f:= proc(n) local A, i;
A:= [seq(nops(numtheory:-factorset(binomial(n, i))), i=0..n)];
numboccur(max(A), A);
end proc:
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MATHEMATICA
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a[n_] := Sort[Tally[Table[PrimeNu[Binomial[n, k]], {k, 0, n}]]][[-1, 2]];
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PROG
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(PARI) a(n) = {v = vector(n+1, k, omega(binomial(n, k-1))); m = vecmax(v); sum(i=1, n+1, v[i] == m); } \\ Michel Marcus, Dec 30 2013
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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