OFFSET
1,1
LINKS
Jianing Song, Table of n, a(n) for n = 1..10
FORMULA
a(n)/a(n-1) = (7^2^(n-1) + 1)/2 = 2^(n+1) * a(n-1) + 1.
For all n > m, a(n) and a(m) are congruent modulo 2^(m+2) but not modulo 2^(m+3).
PROG
(PARI) a(n) = (7^2^n - 1)/2^(n+3)
(Python)
def A359500(n): return 7**(1<<n)-1>>n+3 # Chai Wah Wu, Jan 15 2023
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Jianing Song, Jan 03 2023
STATUS
approved