OFFSET
1,1
COMMENTS
It appears that the first term of A001008 having a cubic factor is A001008(848) = 11^3 * 1871 * C359.
By Wolstenholme's Theorem, p^2 divides A001008(p-1) whenever p >= 5 is prime (cf. A076637); see A308968 for illustration. Therefore, A006093 \ {1, 2} (primes - 1) is a subsequence. (Thanks to Bernard Schott.)
PROG
CROSSREFS
KEYWORD
nonn,more,hard
AUTHOR
M. F. Hasler, Jul 03 2019
STATUS
approved