OFFSET
0,1
COMMENTS
Probably, the last nonzero term is a(401) = 2^71*3^45*5^9*7^4. - Giovanni Resta, Jul 14 2015
LINKS
Vincenzo Librandi, Table of n, a(n) for n = 0..1000
FORMULA
EXAMPLE
9349 is the 19th Lucas number; its digit product is 972, therefore a(19) = 972.
15127 is the 20th Lucas number; its digit product is 70, therefore a(20) = 70.
MATHEMATICA
Table[Times@@IntegerDigits[LucasL[n]], {n, 0, 100}]
PROG
(Magma) [&*Intseq(Lucas(n)): n in [0..80]];
CROSSREFS
KEYWORD
nonn,base
AUTHOR
Vincenzo Librandi, Jul 05 2015
STATUS
approved