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A230137
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a(n)/2^n is the expected value of the maximum of the number of heads and the number of tails when n fair coins are tossed.
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2
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0, 2, 6, 18, 44, 110, 252, 588, 1304, 2934, 6380, 14036, 30120, 65260, 138712, 297240, 627248, 1332902, 2796876, 5904516, 12333320, 25899972, 53897096, 112693928, 233776464, 487034300, 1007623032, 2092755528, 4319728784, 8948009624, 18432890160, 38094639664
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OFFSET
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0,2
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LINKS
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FORMULA
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a(2n) = 2*Sum_{k=n+1..2n} binomial(2n,k)*k + binomial(2n,n)*n.
a(2n+1) = 2*Sum_{k=n+1..2n+1} binomial(2n+1,k)*k.
a(n) = 2*n/(n-1)*a(n-1) +4*(n-3)/(n-2)*a(n-2) -8*a(n-3) for n>2, else a(n) = n*(1+n). - Alois P. Heinz, Oct 10 2013
a(2*n) = (4^n + binomial(2*n,n))*n.
a(2*n+1) = (4^n + binomial(2*n,n))*(2*n+1). (End)
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EXAMPLE
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a(2) = 6 because there are four possible events when 2 coins are tossed: HH, HT, TH, TT. The maximum of the number of heads and number of tails is respectively: 2 + 1 + 1 + 2 = 6.
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MAPLE
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a:= proc(n) option remember; `if`(n<3, n*(1+n),
2*n/(n-1)*a(n-1) +4*(n-3)/(n-2)*a(n-2) -8*a(n-3))
end:
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MATHEMATICA
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nn=15; even=Table[n 2^(2n)+n Binomial[2n, n], {n, 0, nn}]; odd=Table[2Sum[ Binomial[2n+1, k]k, {k, n+1, 2n+1}], {n, 0, nn}]; Riffle[even, odd]
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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