login
A228125
Triangle read by rows: T(n,k) = number of semistandard Young tableaux with sum of entries equal to n and shape of tableau a partition of k.
5
1, 1, 1, 1, 2, 1, 1, 3, 2, 1, 1, 4, 4, 2, 1, 1, 5, 7, 5, 2, 1, 1, 6, 10, 9, 5, 2, 1, 1, 7, 14, 16, 10, 5, 2, 1, 1, 8, 19, 24, 19, 11, 5, 2, 1, 1, 9, 24, 37, 32, 21, 11, 5, 2, 1, 1, 10, 30, 51, 52, 38, 22, 11, 5, 2, 1, 1, 11, 37, 71, 79, 66, 41, 23, 11, 5, 2, 1, 1, 12, 44, 93, 117, 106, 74, 43, 23, 11, 5, 2, 1, 1, 13, 52, 122, 166, 166, 125, 80, 44, 23, 11, 5, 2, 1, 1, 14, 61, 153, 231, 251, 204, 139, 83, 45, 23, 11, 5, 2, 1, 1, 15, 70, 193, 311, 367, 322, 236, 147, 85, 45, 23, 11, 5, 2, 1
OFFSET
1,5
COMMENTS
Row sums equal A003293.
Reverse of rows seem to converge to A005986: 1, 2, 5, 11, 23, 45, 87, 160, ...
EXAMPLE
T(6,3) = 7 since the 7 SSYT with sum of entries = 6 and shape any partition of 3 are
114 , 123 , 222 , 11 , 12 , 13 , 1
4 3 2 2
3
Triangle starts:
1;
1, 1;
1, 2, 1;
1, 3, 2, 1;
1, 4, 4, 2, 1;
1, 5, 7, 5, 2, 1;
1, 6, 10, 9, 5, 2, 1;
1, 7, 14, 16, 10, 5, 2, 1;
1, 8, 19, 24, 19, 11, 5, 2, 1;
1, 9, 24, 37, 32, 21, 11, 5, 2, 1;
1, 10, 30, 51, 52, 38, 22, 11, 5, 2, 1;
MATHEMATICA
hooklength[(par_)?PartitionQ]:=Table[Count[par, q_ /; q>=j] +1-i +par[[i]] -j, {i, Length[par]}, {j, par[[i]]} ];
Table[Tr[(SeriesCoefficient[q^(#1 . Range[Length[#1]])/Times @@ (1-q^#1&) /@ Flatten[hooklength[#1]], {q, 0, w}]&) /@ Partitions[n]], {w, 24}, {n, w}]
CROSSREFS
Sequence in context: A092905 A052509 A172119 * A227588 A093628 A186807
KEYWORD
nonn,tabl
AUTHOR
Wouter Meeussen, Aug 11 2013
STATUS
approved