

A189761


Numbers n for which the set of residues {Fibonacci(k) mod n, k=0,1,2,....} is minimal.


1



1, 2, 3, 4, 5, 8, 11, 21, 29, 55, 76, 144, 199, 377, 521, 987, 1364, 2584, 3571, 6765, 9349, 17711, 24476, 46368, 64079, 121393, 167761, 317811, 439204, 832040, 1149851, 2178309, 3010349, 5702887, 7881196, 14930352, 20633239, 39088169, 54018521, 102334155
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OFFSET

1,2


COMMENTS

Sequence A066853 gives the number of possible residues of the Fibonacci numbers mod n. For the n in this sequence, it appears that A066853(n) < A066853(m) for all m > n. For these n, the set of residues consists of Fibonacci numbers < n and some of their negatives (see example).
Interestingly, for n > 5, this sequence alternates the evenindex Fibonacci and oddindex Lucas numbers, A001906 and A002878. See A109794 for the sequence without 2 and 5.
The number of residues is 1, 2, 3, 4, 5, 6, 7, 9, 10, 12, 13, 15, 16,..., which is A032766 with 2 and 5 included.


LINKS

Table of n, a(n) for n=1..40.
Index entries for linear recurrences with constant coefficients, signature (0,3,0,1).


FORMULA

From Colin Barker, Oct 29 2013: (Start)
a(n) = 3*a(n2)a(n4) for n>9.
G.f.: x*(x^8+x^7x^62*x^53*x^42*x^3+2*x+1) / ((x^2x1)*(x^2+x1)). (End)


EXAMPLE

For n=55, the residues are {0, 1, 2, 3, 5, 8, 13, 21, 34, 47, 52, 54} which can also be written as {0, 1, 2, 3, 5, 8, 13, 21, 21, 8, 3, 1}.


MATHEMATICA

Union[{2, 5}, Fibonacci[Range[2, 20, 2]], LucasL[Range[1, 20, 2]]]


PROG

(PARI) Vec(x*(x^8+x^7x^62*x^53*x^42*x^3+2*x+1)/((x^2x1)*(x^2+x1)) + O(x^100)) \\ Colin Barker, Oct 29 2013


CROSSREFS

Cf. A001906, A002878, A032766, A066853, A109794, A189768.
Sequence in context: A103262 A135318 A210671 * A101137 A256386 A053021
Adjacent sequences: A189758 A189759 A189760 * A189762 A189763 A189764


KEYWORD

nonn,easy


AUTHOR

T. D. Noe, May 10 2011


STATUS

approved



