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A115247 2^a(n) divides A001935(n) but 2^(a(n)+1) does not. 2
0, 0, 1, 0, 2, 1, 0, 2, 4, 1, 0, 1, 1, 6, 1, 0, 2, 1, 4, 1, 6, 0, 2, 4, 1, 2, 2, 8, 0, 1, 1, 2, 1, 4, 6, 1, 0, 3, 4, 1, 2, 7, 1, 6, 1, 0, 1, 4, 6, 2, 1, 1, 2, 1, 1, 0, 1, 1, 8, 2, 4, 2, 6, 4, 3, 1, 0, 2, 4, 7, 3, 1, 1, 4, 1, 1, 6, 1, 0, 2, 1, 2, 1, 6, 1, 2, 4, 2, 7, 8, 6, 0, 2, 4, 2, 1, 1, 6, 4, 4 (list; graph; refs; listen; history; internal format)
OFFSET

0,5

COMMENTS

Almost all members of A001935 are divisible by 2^k for any k, therefore almost all a(n)>k for any k.

LINKS

Basil Gordon and Ken Ono, Divisibility of Certain Partition Functions By Powers of Primes.

K. Alladi, Partition Identities Involving Gaps and Weights, Transactions of the American Mathematical Society, Vol. 349, No. 12, Dec 1997, pp. 5001-5019.

CROSSREFS

The 0's are in A000217. The 1's are in A115248. Least inverse A115250.

Sequence in context: A144106 A104558 A206022 * A204163 A122542 A098542

Adjacent sequences:  A115244 A115245 A115246 * A115248 A115249 A115250

KEYWORD

nonn

AUTHOR

Christian G. Bower (bowerc(AT)usa.net), Jan 17 2006

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Last modified February 16 05:55 EST 2012. Contains 205860 sequences.