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A076978
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Product of the distinct primes dividing the product of composite numbers between consecutive primes.
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9
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1, 2, 6, 30, 6, 210, 6, 2310, 2730, 30, 39270, 7410, 42, 7590, 46410, 1272810, 30, 930930, 82110, 6, 21111090, 1230, 48969690, 1738215570, 2310, 102, 144690, 6, 85470, 29594505363092670, 16770, 49990710, 138, 7849357706190, 30, 300690390, 20223210, 1122990, 37916970
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OFFSET
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1,2
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COMMENTS
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Equivalently, the largest squarefree number that divides the product of composite numbers between successive primes.
All terms greater than one are even.
Omega(a(n)): 0, 1, 2, 3, 2, 4, 2, 5, 5, 3, 6, 5, 3, 5, 6, 7, 3, 7, 6, 2, 8, 4, 8, 9, 5, ..., .
Records: 1, 2, 6, 30, 210, 2310, 2730, 39270, 46410, 1272810, 21111090, ..., (2*A354218).
Factored: 1, 2, 2*3, 2*3*5, 2*3*5*7, 2*3*5*7*11, 2*3*5*7*13, 2*3*5*7*11*17, 2*3*5*7*13*17, 2*3*5*7*11*19*29, ..., .
(End)
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LINKS
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FORMULA
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EXAMPLE
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a(4) = product of prime divisors of the product of composite numbers between 7 and 11 = 2 * 3 * 5 = 30.
a(5)=6 because 12 is the only composite number between the 5th and the 6th primes (11 and 13) and largest squarefree divisor of 12 is 6.
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MAPLE
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with(numtheory): b:=proc(j) if issqrfree(j) then j else fi end: a:=proc(n) local B, BB: B:=divisors(product(i, i=ithprime(n)+1..ithprime(n+1)-1)): BB:=(seq(b(B[j]), j=1..nops(B))): max(BB); end: seq(a(n), n=1..33); # Emeric Deutsch, Jul 28 2006
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MATHEMATICA
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f[n_] := Times @@ (First@# & /@ FactorInteger[Times @@ Range[Prime[n] + 1, Prime[n + 1] - 1]]); Array[f, 50] (* Robert G. Wilson v, Dec 02 2020 *)
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PROG
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(PARI) a(n) = my(p=1); forcomposite(c=prime(n), prime(n+1), p*=c); factorback(factorint(p)[, 1]); \\ Michel Marcus, May 29 2022
(Python) from sympy import sieve as p, primefactors
result = 1
for composites in range(p[n]+1, p[n+1]):
for primefactor in primefactors(composites):
if result % primefactor != 0: result *= primefactor
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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