

A014847


Numbers k such that kth Catalan number C(2k,k)/(k+1) is divisible by k.


20



1, 2, 6, 15, 20, 28, 42, 45, 66, 77, 88, 91, 104, 110, 126, 140, 153, 156, 170, 187, 190, 204, 209, 210, 220, 228, 231, 238, 240, 266, 276, 299, 308, 312, 315, 322, 325, 330, 345, 368, 378, 414, 420, 429, 435, 440, 442, 450, 459, 460, 464, 468, 476, 483, 493
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OFFSET

1,2


COMMENTS

The sequence does not contain any odd primes p (follows by quadratic reciprocity and field structure of Z/pZ). Aside from the first 2 terms, all other terms are composite integers.  Thomas M. Bridge, Nov 03 2013
Equivalently, numbers such that binomial(2n, n) = 0 (mod n). Indices of zeros in A059288. See A260640 (and A260636) for the analogs for 3n.  M. F. Hasler, Nov 11 2015
The 2nd comment is true because gcd(n,n+1) = 1 and n+1 divides C(2n,n). The 1st comment then follows, because prime p does not divide C(2p,p) = 2p*(2p1)*...*(p+1)/(p*(p1)*...*1) unless p = 2.  Jonathan Sondow, Jan 07 2018
A number n is in the sequence if and only if, for each prime p dividing n, the number of carries in the addition n+n in base p is at least the padic valuation of n. In particular, if n is squarefree, the condition is that at least one basep digit of n is at least p/2.  Robert Israel, Jan 07 2018
If A is the set of all a(k)'s, Pomerance proved that the upper density of A is at most 1  log 2 = 0.30685... and conjectured that A has positive lower density. I improved Pomerance's result by showing that the upper density of A is at most 1  log 2  0.05551 = 0.25134... Numerically, this upper density seems to be less than 0.11.  Carlo Sanna, Jan 28 2018


LINKS

Franklin T. AdamsWatters and Chai Wah Wu, Table of n, a(n) for n = 1..10000 n=1..1069 (a(n) <= 10000) from Franklin T. AdamsWatters
M. Alekseyev, PARI/GP Scripts for Miscellaneous Math Problems, sect. III: Binomial coefficients modulo integers, binomod.gp (V. 1.4, 11/2015).
Christian Ballot, Lucasnomial FussCatalan Numbers and Related Divisibility Questions, J. Int. Seq., Vol. 21 (2018), Article 18.6.5.
C. Pomerance, Divisors of the middle binomial coefficient, Amer. Math. Monthly, 112 (2015), 636644.
C. Sanna, Central binomial coefficients divisible by or coprime to their indices, Int. J. Number Theory (2018).
Eric Weisstein's World of Mathematics, Disk Line Picking


FORMULA

It seems that a(n)/n is bounded and more precisely that lim_{n > infinity} a(n)/n = C exists with 9 <= c < 10.  Benoit Cloitre, Aug 13 2002
a(n) = A004782(n)  1.  Enrique Pérez Herrero, Feb 03 2013


MAPLE

filter:= proc(n) local F, f, r, c, t, j;
F:= ifactors(n)[2];
for f in F do
r:= convert(n, base, f[1]);
c:= 0: t:= 0:
for j from 1 to nops(r) do
if 2*r[j]+c >= f[1] then
c:= 1; t:= t+1;
else c:= 0
fi;
od;
if t < f[2] then return false fi;
od;
true
end proc:
select(filter, [$1..1000]); # Robert Israel, Jan 07 2018


MATHEMATICA

fQ[n_] := IntegerQ[Binomial[2n, n]/ n]; Select[ Range@495, fQ@# &] (* Robert G. Wilson v, Jun 19 2006 *)


PROG

(PARI) is_A014847(n)=!binomod(2*n, n, n) \\ Suitable for large n. Using binomod.gp by M. Alekseyev, cf. links.  M. F. Hasler, Nov 11 2015
(PARI) for(n=1, 1e3, if(binomial(2*n, n)/(n+1) % n==0, print1(n", "))) \\ Altug Alkan, Nov 11 2015
(Python)
from __future__ import division
A014847_list, b = [], 1
for n in range(1, 10**3):
if not b % n:
A014847_list.append(n)
b = b*(4*n+2)//(n+2) # Chai Wah Wu, Jan 27 2016
(MAGMA) [n: n in [1..500]  IsZero((Binomial(2*n, n) div (n+1)) mod n)]; // Vincenzo Librandi, Jan 29 2016


CROSSREFS

Cf. A000108, A000984, A120622, A120623, A120624, A120625, A120626, A121943, A282163, A282346, A283073, A283074, A282672.
Sequence in context: A294942 A227307 A129631 * A013636 A144653 A276782
Adjacent sequences: A014844 A014845 A014846 * A014848 A014849 A014850


KEYWORD

nonn


AUTHOR

N. J. A. Sloane


STATUS

approved



