OFFSET
1,1
COMMENTS
The number of free subgroups of index 12*n+{1,...,11} is 0, hence sequence is only for 12*n.
LINKS
Wilfried Imrich, On the number of subgroups of given index in SL_2(Z), Archiv der Mathematik, vol. 31, 1978, pp. 224-231.
FORMULA
a(n) = 12*n*a(n-1) + Sum_{k = 1 .. n-2} a(k)*a(n-1-k) (Theorem 2 from Imrich).
MAPLE
a := proc(n) option remember: local i: if n = 1 then 20:
else 12*n*a(n-1)+add(a(k)*a(n-1-k), k = 1 .. n-2): fi: end:
seq(a(n), n = 1 .. 16);
CROSSREFS
KEYWORD
nonn
AUTHOR
Lorenzo Sauras Altuzarra, Apr 24 2026
STATUS
approved
