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A394170
Decimal expansion of the mean volume of a tetrahedron whose vertices are uniformly and independently selected at random in the interior of a regular octahedron of unit volume.
7
0, 1, 3, 6, 3, 7, 4, 1, 1, 2, 7, 6, 5, 2, 4, 1, 7, 5, 4, 6, 0, 2, 1, 2, 3, 1, 5, 3, 2, 9, 9, 6, 7, 7, 9, 8, 2, 9, 3, 2, 3, 8, 4, 7, 7, 8, 7, 4, 9, 5, 2, 8, 7, 7, 8, 6, 4, 6, 4, 3, 6, 2, 1, 0, 2, 6, 4, 3, 4, 9, 0, 3, 1, 8, 8, 3, 6, 2, 8, 7, 0, 6, 9, 8, 9, 7, 2, 5, 2, 6, 0, 9, 4, 9, 7, 0, 1, 9, 5, 3, 6, 4, 7, 5, 0, 2
OFFSET
0,3
COMMENTS
The problem of calculating this constant was mentioned by Zinani (2003). It was evaluated by Weisstein as 0.01368, and calculated by Beck (2022).
LINKS
Dominik Beck, On Random Simplex Picking Beyond the Blashke Problem, arXiv:2412.07952 [math.MG], 2024.
Dominik Beck, Random polytopes, doctoral thesis, Mathematical Institute of Charles University, Prague, 2025.
Eric Weisstein's World of Mathematics, Octahedron Tetrahedron Picking.
Alessandro Zinani, The expected volume of a tetrahedron whose vertices are chosen at random in the interior of a cube, Monatshefte für Mathematik, Vol. 139, No. 4 (2003), pp. 341-348.
FORMULA
Equals 19297*Pi^2/3843840 - 6619/184320.
EXAMPLE
0.0136374112765241754602123153299677982932384778749528...
MATHEMATICA
RealDigits[19297*Pi^2/3843840 - 6619/184320, 10, 120, -1][[1]]
PROG
(PARI) 19297*Pi^2/3843840 - 6619/184320
CROSSREFS
Tetrahedron volume in: A093524 (cube), A093525 (tetrahedron), A093591 (ball), A394169 (surface of sphere), this constant (octahedron), A394171 (rhombic dodecahedron), A394172 (cuboctahedron), A394173 (truncated tetrahedron), A394174 (triangular bipyramid), A394175 (triangular prism), A394176 (square pyramid).
Sequence in context: A170859 A123146 A396028 * A016661 A376827 A378935
KEYWORD
nonn,cons
AUTHOR
Amiram Eldar, Mar 11 2026
STATUS
approved