OFFSET
1,1
COMMENTS
Let q = A053669(k) be the smallest prime such that gcd(k,q) = 1. Let squarefree kernel rad = A007947 and let m = A003557(k) = k/rad(k). Then k is in this sequence if q < m.
{a(n)} \ A001694 = {1, 4}.
Terms are such that there exists a number j < k such that rad(k) | gcd(j,k). This is to say that, though rad(k) | j, j has a factor greater than 1 that does not divide k.
LINKS
Michael De Vlieger, Table of n, a(n) for n = 1..10000
Michael De Vlieger, Diagram showing j <= k, n = 1..72, where a number k is a term of this sequence (written at right in red) for which there exists at least one j <= k (highlighted in blue, which appear in row k of A272619) such that gcd(j,k) > 1, rad(j) does not divide k, but rad(k) | j. Green dots also appear in row k of A272619 but in those cases, rad(k) does not divide j.
Michael De Vlieger, Plot j < k at (x,y) = (j,k), k = 1..1024, such that gcd(j,k) > 1, rad(j) does not divide k, and rad(k) | j. In the plot, j increases toward the right and k increases downward.
EXAMPLE
Let r = rad(a(n)) and m = A381803(n).
Table of n, a(n), r, and j for select n:
n a(n) r j
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1 8 2 {6}
2 9 3 {6}
3 16 2 {6, 10, 12, 14}
4 25 5 {10, 15, 20}
5 27 3 {6, 12, 15, 18, 21, 24}
6 32 2 {6, 10, 12, 14, 18, 20, 22, 24, 26, 28, 30}
7 36 6 {30}
8 40 10 {30}
17 72 6 {30, 42, 60, 66}
35 144 6 {30, 42, 60, 66, ..., 138}
56 240 30 {210}
1331 5184 6 {30, 42, 60, 66, ..., 5178}
MATHEMATICA
rad[x_] := Times @@ FactorInteger[x][[All, 1]]; a053669[x_] := Module[{qx}, qx = 2; While[Divisible[x, qx], qx = NextPrime[qx]]; qx]; Select[Range[250], a053669[#] < #/rad[#] &]
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Michael De Vlieger, Jun 02 2026
STATUS
approved
