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A393095
Group the partitions of n into 3 parts into sets whose smallest parts are equal. a(n) is the sum of the minimum values of all the largest parts in each set.
1
0, 0, 0, 1, 2, 2, 5, 6, 7, 11, 13, 14, 20, 22, 24, 31, 34, 36, 45, 48, 51, 61, 65, 68, 80, 84, 88, 101, 106, 110, 125, 130, 135, 151, 157, 162, 180, 186, 192, 211, 218, 224, 245, 252, 259, 281, 289, 296, 320, 328, 336, 361, 370, 378, 405, 414, 423, 451, 461, 470, 500, 510, 520, 551, 562, 572, 605, 616, 627, 661, 673, 684, 720, 732, 744, 781
OFFSET
0,5
FORMULA
G.f.: x^3*(1+2*x+x^2+x^3)/((1-x)^3*(1+x)*(1+x+x^2)^2).
a(n) = a(n-2) + 2*a(n-3) - 2*a(n-5) - a(n-6) + a(n-8).
a(n) = Sum_{j=1..floor(n/3)} ceiling((n-j)/2).
a(n) = floor(n/3)*(2*n-1-floor(n/3))/4-floor((n-2)/3)/2+floor((n-2)/2)/2.
a(n) = A211546(n) - A393093(n).
EXAMPLE
a(10) = 13; The partitions of 10 into 3 parts grouped by smallest part: {(8,1,1),(7,2,1),(6,3,1),(5,4,1)}, {(6,2,2),(5,3,2),(4,4,2)}, {(4,3,3)}. The sum of the minimum values of all the largest parts in each set is 5+4+4 = 13.
MATHEMATICA
CoefficientList[Series[x^3*(1 + 2*x + x^2 + x^3)/((1 - x)^3*(1 + x)*(1 + x + x^2)^2), {x, 0, 80}], x]
LinearRecurrence[{0, 1, 2, 0, -2, -1, 0, 1}, {0, 0, 0, 1, 2, 2, 5, 6}, 80]
Table[Floor[n/3] (2 n - 1 - Floor[n/3])/4 - Floor[(n - 2)/3]/2 + Floor[(n - 2)/2]/2, {n, 0, 80}]
CROSSREFS
Cf. A069905, A211546, A393093 (sum of maximums of middle parts).
Sequence in context: A054255 A063177 A249521 * A355345 A034803 A205885
KEYWORD
nonn,easy
AUTHOR
Wesley Ivan Hurt, Feb 01 2026
STATUS
approved