OFFSET
1,1
COMMENTS
This sequence is an exact equivalent of A006039 (the primitive nondeficient numbers), the difference being A006039 requires the abundancy ratio, sigma(k)/k, to be at least 2, whereas here we use 6. - Peter Munn, Feb 12 2026
The term with the greatest abundancy ratio is 204773655626139600 = A307111(6). - Peter Munn, Jun 05 2026
LINKS
Eric Weisstein's World of Mathematics, Abundancy.
FORMULA
{a(n)} = {k >= 2 : A000203(k) >= 6k and A000203(A395192(k)) < 6*A395192(k)}. - Peter Munn, Jun 05 2026
EXAMPLE
130429015516800 is in the sequence as sigma(130429015516800)/130429015516800 >= 6 but none of its divisors d has sigma(d)/d >= 6.
PROG
(PARI) is(n) = {my(f = factor(n)); if(sigma(f) < 6*n, return(0)); for(i = 1, #f~, c = n\f[i, 1]; if(sigma(c) >= 6*c, return(0))); 1}
CROSSREFS
KEYWORD
nonn,changed
AUTHOR
David A. Corneth, Jan 30 2026
STATUS
approved
