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A392740
5-smooth numbers k = s(i) such that s(i)/s(i+1) sets a record high, where s = A051037.
3
1, 2, 3, 4, 5, 8, 9, 15, 24, 80, 2025, 15552, 32768, 274658203125, 7625597484987, 9007199254740992, 450283905890997363, 381469726562500000000000000000, 17763086495282268024161967871623168, 2922977339492680612451840826835216578535400390625
OFFSET
1,2
COMMENTS
No larger terms for n <= s(78738133) = 2^1200.
LINKS
Michael De Vlieger, Table of n, a(n) for n = 1..22
EXAMPLE
Let facs(x) represent the standard form prime decomposition of x.
Table of n, a(n) = s(i) for n = 1..22:
n i a(n) facs(s(i)) facs(s(i+1))
-------------------------------------------------
1 1 1 1 2
2 2 2 2 3
3 3 3 3 2^2
4 4 4 2^2 5
5 5 5 5 2 * 3
6 7 8 2^3 3^2
7 8 9 3^2 2 * 5
8 11 15 3 * 5 2^4
9 15 24 2^3 * 3 5^2
10 30 80 2^4 * 5 3^4
11 109 2025 3^4 * 5^2 2^11
12 197 15552 2^6 * 3^5 5^6
13 240 32768 2^15 3^8 * 5
14 2993 3^2 * 5^15 2^38
15 4190 3^27 2 * 5^18
16 7716 2^53 3^10 * 5^16
17 10322 3^37 2^54 * 5^2
18 46264 2^17 * 5^35 3^62
19 71093 2^90 * 3^15 5^49
20 197754 3^84 * 5^12 2^161
21 5105847 5^207 2^21 * 3^290
22 8629955 2^573 3^237 * 5^85
MATHEMATICA
s = Block[{n = 2^60}, Union@ Flatten@ Table[2^i * 3^j * 5^k, {i, 0, Log[2, n]}, {j, 0, Log[3, n/2^i]}, {k, 0, Log[5, n/(2^i * 3^j)]} ] ]; Numerator@ Union@ FoldList[Max, Divide @@@ Partition[s, 2, 1] ]
CROSSREFS
KEYWORD
nonn
AUTHOR
Zhicheng Wei, Feb 25 2026
STATUS
approved