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A392135
Third column of A391957.
2
0, 0, 0, 0, 0, 9, 7, 5, 3, 1, 18, 14, 10, 6, 2, 27, 21, 15, 9, 3, 36, 28, 20, 12, 4, 94, 82, 70, 58, 46, 93, 79, 65, 51, 37, 92, 76, 60, 44, 28, 91, 73, 55, 37, 19, 90, 70, 50, 30, 10, 188, 164, 140, 116, 92, 177, 151, 125, 99, 73, 166, 138, 110, 82, 54, 155, 125
OFFSET
0,6
COMMENTS
Powers of 5 in the factorization of A391956.
The first 82 terms were obtained from a brute force calculation of A391956. From these results a regular pattern is observed to determine more terms.
See also A391957 for a Python program.
LINKS
FORMULA
a(5^n) = 5*a(5^(n-1)) + 2*5^n - 1, a(1) = 0.
Conjectured: a(j*5^m + 5^(m-1)*k) = a(j*5^m) + k*(a(5^(m-1)) - 2*5^(m-1)*Sum_{i = 1..j} A055457(i)), 0 < k < 5, where a(j*5^m) = j*a(5^(m-1)) for j < 5.
CROSSREFS
KEYWORD
nonn
AUTHOR
A.H.M. Smeets, Jan 01 2026
STATUS
approved