OFFSET
0,3
FORMULA
Conjecture: A(n,0) = A233335(n+1).
EXAMPLE
Array begins:
============================================================================
n\k| 0 1 2 3 4 5 6 ...
---+------------------------------------------------------------------------
0 | 1 1 1 1 1 1 1 ...
1 | 2 5 17 83 578 5474 66932 ...
2 | 7 31 178 1330 12748 153136 2249503 ...
3 | 38 254 2099 21338 263870 3913556 68599898 ...
4 | 292 2683 29425 382966 5865952 104739142 2158835605 ...
5 | 2975 35375 489383 7837136 144383006 3039205823 72586944074 ...
6 | 38350 566083 9538360 182707696 3959710333 96600644167 2639032949860 ...
...
PROG
(PARI) antidiagonals(n) = {my(v = vector(n+1, i, vector(n-i+2, j, i==1)));
for(i=1, n, forstep(j=i-1, 0, -1, v[i-j+1][j+1] = v[i-j][j+2] + sum(k=0, j, binomial(j+1, k)*v[i-j][k+1]*v[j-k+1][1])));
v = vector(n+1, i, vector(i, j, v[j][i-j+1]))}
CROSSREFS
KEYWORD
nonn,tabl
AUTHOR
Mikhail Kurkov, Dec 29 2025
STATUS
approved
