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A390860
a(n) is the minimum number of armies required for an attacker to have a 50% or better chance of beating a defender with n armies in the game Risk.
1
3, 4, 5, 6, 6, 7, 8, 9, 10, 11, 12, 12, 13, 14, 15, 16, 17, 18, 18, 19, 20, 21, 22, 23, 24, 24, 25, 26, 27, 28, 29, 30, 30, 31, 32, 33, 34, 35, 35, 36, 37, 38, 39, 40, 41, 41, 42, 43, 44, 45, 46, 47, 47, 48, 49, 50, 51, 52, 53, 53, 54, 55, 56, 57, 58, 59, 59
OFFSET
1,1
COMMENTS
In the game Risk, battles are settled by dice roll. Attackers get one red die per army (up to 3 dice) and defenders get one white die per army (up to 2 dice). The highest attacker die is paired with the highest defender die, and 2nd highest with 2nd highest. The attacker must have at least one more army than the number of dice rolled, since one army must be left behind occupying the original attacker space. Ties are won by the defender, which gives defenders a significant advantage. Losing a dice roll corresponds to losing an army, which can change the number of dice that can be rolled.
The defender has a significant advantage when smaller numbers of armies are involved. However, as the number of armies increases, the 3:2 attacker to defender dice ratio increases the likelihood of the attacker winning. Thus, a(n) < k for k >= 19.
LINKS
Sharon Blatt, RISKy Business: An In-Depth Look at the Game RISK, Rose-Hulman Undergraduate Mathematics Journal, Vol. 3: Iss. 2, Article 3.
Daniel Morris and Megan Vance, Risk and Markov Chains.
FORMULA
a(n) = 1 + min{k : A371949(k, mN) / 7776^(n+k-1) >= 1/2}. - Sean A. Irvine, Dec 12 2025
EXAMPLE
For example, suppose the attacker has 4 armies and is attacking a defender with just 1. The attacker can roll 3 dice against 1 for the defender. Here is a sample battle:
Attacker Defender
Roll 1: 5 3 2 6 --> Defender wins and attacker loses one army
Roll 2: 5 1 4 --> Attacker wins and occupies defender's space
If an attacker with 2 armies attacks a defender with just 1, the attacker loses more than 50% of the time. But with 3 armies, the odds favor the attacker, so a(1) = 3.
Similarly, if a defender has 4 armies then an attacker must have at least 6 armies to have a 50% chance of winning an attack, so a(4) = 6.
CROSSREFS
Sequence in context: A217031 A104136 A198466 * A212642 A159624 A036288
KEYWORD
nonn
AUTHOR
EXTENSIONS
More terms from Sean A. Irvine, Dec 12 2025
STATUS
approved