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A390507
a(n) = number of 1's in A390505(n).
2
1, 2, 1, 3, 3, 2, 2, 3, 4, 3, 3, 5, 3, 3, 1, 4, 4, 3, 4, 6, 4, 4, 4, 5, 6, 5, 3, 5, 4, 2, 2, 3, 5, 4, 4, 6, 4, 4, 5, 6, 7, 6, 4, 6, 5, 3, 3, 6, 6, 5, 6, 8, 6, 6, 4, 5, 6, 5, 4, 6, 3, 3, 2, 4, 4, 3, 5, 7, 5, 5, 5, 6, 7, 6, 4, 6, 5, 3, 4, 7, 7, 6, 7, 9, 7, 7
OFFSET
1,2
FORMULA
a(n) = A007953(A390505(n)).
EXAMPLE
A390505(20) = 10111011, so a(2) = 6.
MATHEMATICA
f[w_] := StringJoin[Map[IntegerString[Length[#], 2] <> ToString[#[[1]]] &, Split[Characters[w]]]];
s[n_] := Map[StringJoin[Map[ToString, Rest[IntegerDigits[#, 2]]]] &, Range[2, 2^(n + 1) - 1]];
m = Map[f, s[6]] (* A390505 *)
m1 = ToExpression /@ Characters /@ m; u = Map[Length, m1]
Table[Count[m1[[n]], 1], {n, 1, 120}] (* A390507 *)
(* Peter J. C. Moses, Nov 05 2025 *)
CROSSREFS
KEYWORD
nonn,base
AUTHOR
Clark Kimberling, Dec 02 2025
STATUS
approved