OFFSET
1,3
COMMENTS
If n is not a multiple of 5, is there always some multiplier k that makes A389140(k*n) collapse to 1?
From Pontus von Brömssen, Sep 27 2025: (Start)
The minimum of A389140(k*n) is at least 15 if n is a multiple of 25 and at least 5 if n is a multiple of 5. It seems that the best of these bounds is attained for all such n, and that the minimum is 1 if n is not a multiple of 5.
It seems that a(4000) = 3 is the last term not equal to 1, 2, or 4. Moreover, it seems that
- a(n) = 1 if n > 8060, and either n == 25, 50 (mod 100) or n is even and not congruent to 10 modulo 20;
- a(n) = 2 if n > 4030, and either n is odd and not congruent to 5 (mod 10) or n == 10, 30, 70, 75, 90 (mod 100);
- a(n) = 4 if n > 2015, n == 5 (mod 10), and n is not a multiple of 25.
(End)
LINKS
Pontus von Brömssen, Table of n, a(n) for n = 1..10000
EXAMPLE
a(3)=18 because 3*18=54, and 54 --> 52 --> 26 --> 16 --> 8 --> 4 --> 2 --> 1.
CROSSREFS
KEYWORD
nonn,base
AUTHOR
Ali Sada, Sep 24 2025
STATUS
approved
