OFFSET
1,2
COMMENTS
Superset of A000079 since P(1)^m * Q(1)^h = 2^(m+h). Intersection of this sequence and A000961 = A000079.
Proper subset of A025487 (i.e., products of primorials), which in turn is a proper subset of A055932 (i.e., numbers with a primorial squarefree kernel).
Squarefree numbers in this sequence are {1, 2}.
LINKS
Michael De Vlieger, Table of n, a(n) for n = 1..10000
EXAMPLE
Table of n, a(n) for select n showing p-adic valuation of a(n) for p | a(n):
p-adic valuation
n a(n) 2 3 5 7
-----------------------------------------
1 1 = P(0)^m * Q(0)^h
2 2 = 2^1 1
3 4 = 2^2 2
4 8 = 2^3 3
5 12 = P(2)^0 * Q(2)^1 2.1
9 72 = P(2)^1 * Q(2)^1 3.2
11 144 = P(2)^1 * Q(2)^2 4.2
13 360 = P(3)^0 * Q(3)^1 3.2.1
25 10800 = P(3)^1 * Q(3)^1 4.3.2
33 75600 = P(4)^0 * Q(4)^1 4.3.2.1
36 129600 = P(3)^0 * Q(3)^2 6.4.2
41 324000 = P(3)^2 * Q(3)^1 5.4.3
53 3888000 = P(3)^1 * Q(3)^2 7.5.3
61 15876000 = P(4)^1 * Q(4)^1 5.4.3.2
MATHEMATICA
nn = 2^30; k = 1; P = 2; Q = 2;
{1}~Join~Union@ Reap[
While[i = 1;
While[j = 0;
While[Q^i*P^j < nn, Sow[Q^i*P^j]; j++]; j > 0, i++];
i > 1, k++; P *= Prime[k]; Q *= P] ][[-1, 1]]
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Michael De Vlieger, Sep 10 2025
STATUS
approved
