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A385189
Intersection of A055932 and A002378.
4
2, 6, 12, 30, 72, 90, 210, 240, 420, 600, 1260, 6480, 15750, 50400, 147840, 194040, 291060, 510510, 2942940, 4324320, 5762400, 9147600, 19136250, 96049800, 153153000, 15178363200, 37822664880, 401392571580
OFFSET
1,1
COMMENTS
These numbers are the products of two consecutive integers and also their squarefree part a primorial.
The last is 633555*633556 = 401392571580. See proof of finiteness in Clements link.
REFERENCES
Ken Clements, Proof that the Equation A! x B! = C! Has Only One Solution for Integers 1 < A < B < C-1, submitted to INTEGERS, 2025.
FORMULA
A007947(a(n)) is in A002110.
EXAMPLE
a(1) = 2 = 1*2 = 2^1.
a(2) = 6 = 2*3 = 2^1 * 3^1.
a(3) = 12 = 3*4 = 2^2 * 3^1.
a(4) = 30 = 5*6 = 2^1 * 3^1 * 5^1.
a(5) = 72 = 8*9 = 2^3 * 3^2.
a(6) = 90 = 9*10 = 2^1 * 3^2 * 5^1.
MAPLE
q:= n-> (s-> nops(s)=numtheory[pi](max(s)))({ifactors(n)[2][.., 1][]}):
select(q, [i*(i+1)$i=1..640000])[]; # Alois P. Heinz, Jun 24 2025
MATHEMATICA
Select[(#*(# + 1)) & /@ Range[633555], PrimePi[(f = FactorInteger[#1])[[-1, 1]]] == Length[f] &] (* Amiram Eldar, Jun 22 2025 *)
PROG
(Python)
from sympy import prime, primefactors
def is_pi_complete(n): # Check for complete set of
factors = primefactors(n) # prime factors
return factors[-1] == prime(len(factors))
def aupto(limit):
result = []
for i in range(1, limit+1):
n = i * (i+1)
if is_pi_complete(n):
result.append(n)
return result
print(aupto(100_000_000))
(PARI) lista(nn) = my(list=List()); for (n=1, nn, my(f=factor(n*(n+1))[, 1]~); if (f==primes(#f), listput(list, n*(n+1)))); Vec(list); \\ Michel Marcus, Jun 22 2025
CROSSREFS
KEYWORD
nonn,fini,full
AUTHOR
Ken Clements, Jun 20 2025
STATUS
approved