login
A384038
Number of 2n X 2n matrices M over GF(2) such that the column space of M is equal to the null space of M.
0
1, 3, 210, 234360, 4047865920, 1092146608143360, 4650098142288472473600, 314462403262051153026062745600, 338960040818652280796119613717033779200, 5834618256563872511581456247120956565738854809600, 1605370810586153268821245248112723240374305354675084328960000
OFFSET
0,2
COMMENTS
Let M be a 2n X 2n matrix over GF(2) such that the column space of M is equal to the null space of M. Then M is nilpotent and nullity(M) = n and index(M) = 2. If M' is similar to M then the column space of M' equals the null space of M'. Moreover, all such matrices are in the same similarity class (see Hoffman link).
LINKS
D. G. Hoffman, Digraphs of finite linear transformations, Australasian Journal of Combinatorics, 12: 225-238 (1995).
FORMULA
a(n) = A002884(n)*A006098(n).
EXAMPLE
a(1) = 3 because there are 3 matrices of size 2 X 2 over GF(2) with the desired property: {{0, 0}, {1, 0}}, {{0, 1}, {0, 0}}, {{1, 1}, {1, 1}}.
MATHEMATICA
q = 2; b[p_, i_] := Count[p, i]; d[p_, i_] := Sum[j b[p, j], {j, 1, i}] + i Sum[b[p, j], {j, i + 1, Total[p]}]; aut[deg_, p_] := Product[Product[q^(d[p, i] deg) - q^((d[p, i] - k) deg), {k, 1, b[p, i]}], {i, 1, Total[p]}]; Table[Product[2^(2 k) - 2^i, {i, 0, (2 k) - 1}]/aut[1, Table[2, {k}]], {k, 0, 10}]
CROSSREFS
KEYWORD
nonn
AUTHOR
Geoffrey Critzer, May 17 2025
STATUS
approved