OFFSET
0,2
COMMENTS
A totally antisymmetric quasigroup of order 2*n+1 is constructed in a way such that M[i][j] != M[j][i] for i!=j with m = 2*n+1, k = 2 and M[j][i] = k*(j-i) mod m for 0 <= j,i < m.
For any k != 0 mod m the resulting matrix M has the same determinant for each n.
Also the resulting matrix M is circulant and a Latin square.
LINKS
Paolo Xausa, Table of n, a(n) for n = 0..100
H. Michael Damm, Totally anti-symmetric quasigroups for all orders n not equal to 2 or 6, Discrete Math., 307:6 (2007), 715-729.
Wikipedia, Quasigroups
FORMULA
a(n) = n*(2*n+1)^(2*n) = A081131(2*n+1).
EXAMPLE
For n = 1, a(1) = 9 because:
The resulting totally anti-symetric quasigroup has a matrix:
with k = 1:
0, 1, 2,
2, 0, 1,
1, 2, 0
which has a determinant: 9.
with k = 2:
0, 2, 1,
1, 0, 2,
2, 1, 0
has also the same determinant 9.
MATHEMATICA
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Darío Clavijo, May 21 2025
STATUS
approved
