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A382325
Numbers with a record ratio of proper factorizations to nontrivial divisors.
2
4, 16, 32, 64, 128, 192, 256, 384, 512, 576, 768, 864, 1024, 1152, 1536, 1728, 2304, 3456, 4608, 5184, 5760, 6912, 8640, 9216, 10368, 11520, 13824, 17280, 20736, 23040, 25920, 27648, 34560, 41472, 51840, 62208, 69120, 82944, 103680, 138240, 165888, 172800
OFFSET
1,1
COMMENTS
Numbers k that give a record value for A028422(k)/A070824(k).
a(n) = 0 (mod 4), and with prime factors of terms clustering around the smallest primes, it is observed that as n increases, the gcd of a(n)..a(oo) remains among the largest divisors of a(n).
EXAMPLE
a(1)=4: |{{2, 2}}| / |{2}| = 1/1.
a(2)=16: |{{2, 2, 2, 2}, {2, 2, 4}, {2, 8}, {4, 4}}| / |{2, 4, 8}| = 4/3.
a(3)=32: |{{2, 2, 2, 2, 2}, {2, 2, 2, 4}, {2, 2, 8}, {2, 4, 4}, {2, 16}, {4, 8}}| / |{2, 4, 8, 16}| = 6/4.
PROG
(PARI) f_count(x, f=List())={my(r=x/if(#f, vecprod(Vec(f)), 1)); if(r==1, return(if(#f, 1, 0))); my(d, c=0); fordiv(r, d, if(d==1 || d==x || (#f && d<f[#f]), next); listput(f, d); c+=f_count(x, f); listpop(f)); return(c)}
my(mx=0); for(x=1, 200000, my(d=numdiv(x)-2); if(!d, next); my(m=f_count(x)/d); if(m>mx, mx=m; print1(x, ", ")))
CROSSREFS
Subsequence of A025487.
Sequence in context: A326873 A126032 A391762 * A296819 A034713 A374001
KEYWORD
nonn
AUTHOR
Charles L. Hohn, Mar 21 2025
STATUS
approved