OFFSET
1,1
FORMULA
a(n) = m+1 if m>=floor((2^k+2)/5) otherwise a(n) = m where k = floor(log_2(5*n+3))+1 and m = n-2+k.
PROG
(Python)
def A381255(n): return (m:=n-2+(k:=(5*n+3).bit_length()))+(m>=((1<<k)|2)//5)
CROSSREFS
KEYWORD
nonn
AUTHOR
Chai Wah Wu, Apr 21 2025
STATUS
approved
