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A381104
a(n) is the number of prime factors with exponent 1 in the prime factorization of the n-th superabundant number.
1
0, 1, 0, 2, 1, 1, 0, 1, 2, 2, 1, 2, 1, 1, 3, 2, 3, 2, 2, 2, 2, 1, 3, 3, 3, 3, 2, 3, 2, 3, 4, 4, 4, 3, 4, 3, 4, 3, 3, 5, 4, 5, 4, 5, 4, 4, 6, 4, 4, 5, 6, 5, 6, 5, 5, 5, 5, 5, 5, 4, 6, 6, 6, 6, 6, 6, 5, 6, 5, 5, 5, 7, 5, 7, 7, 7, 7, 6, 7, 6, 6, 6, 8, 6, 8, 8, 8, 8, 7, 8, 7, 7, 7, 7, 9, 7, 9, 7, 7, 9, 8, 9, 8, 8, 8
OFFSET
1,4
COMMENTS
Alaoglu and Erdős proved that for all superabundant numbers, the exponents in their prime factorization are non-increasing. Moreover, there is always a sequence of prime factors with exponent 1 at the end of the factorization. The only exceptions for this sequence are 1, 4 and 36.
LINKS
L. Alaoglu and P. Erdős, On highly composite and similar numbers, Trans. Amer. Math. Soc., 56 (1944), 448-469. Errata.
Kevin Broughan, Equivalents of the Riemann Hypothesis, Vol. 1: Arithmetic Equivalents, Cambridge University Press, 2017.
FORMULA
a(n) = A056169(A004394(n)).
EXAMPLE
For n=8 the 8th superabundant number is 48 = 2^4*3^1. Only one prime factor appears with exponent 1 so a(8) = 1.
CROSSREFS
Sequence in context: A259538 A099314 A214341 * A281871 A131334 A004602
KEYWORD
nonn,new
AUTHOR
Agustin T. Besteiro, Feb 14 2025
STATUS
approved