OFFSET
1,2
COMMENTS
The sequence can be regarded as a triangular array read by rows. Each row is a permutation of a block of consecutive numbers; the blocks are disjoint and every positive number belongs to some block. The length of row n is 4n-3 = A016813(n+1), n > 0.
The sequence can also be regarded as a table read by upward antidiagonals. For n>1 row n joins two consecutive antidiagonals.
The sequence is an intra-block permutation of the positive integers.
Generalization of Cantor numbering method.
LINKS
Boris Putievskiy, Table of n, a(n) for n = 1..9730
Boris Putievskiy, Integer Sequences: Irregular Arrays and Intra-Block Permutations, arXiv:2310.18466 [math.CO], 2023.
FORMULA
Linear sequence: (a(1),a(2), ... a(A000384(n+1)) is permutation of the positive integers from 1 to A000384(n+1). ord (a(1),a(2), ... a(A000384(n+1)) = 3, where ord is the order of the permutation.
Triangular array T(n,k) for 1 <= k <= 4n - 3 (see Example): T(n,k) = A000384(n-1) + P(n,k), P(n, k) = -k + 2*m(n) - 1 if k < m(n) and k mod 2 = 1, P(n, k) = m(n) - k if k < m(n) and k mod 2 = 0, P(n, k) = k if k >= m(n) and k mod 2 = 1, P(n, k) = k - m(n) + 1 if k >= m(n) and k mod 2 = 0, where m(n) = 2*n - 1.
EXAMPLE
Triangle array begins:
k= 1 2 3 4 5 6 7 8 9
n=1: 1;
n=2: 5, 2, 4, 3, 6;
n=3: 14, 9, 12, 7, 11, 8, 13, 10, 15;
ord(1,5,2... 10,15) = 3.
For n > 1, each row of triangle array joins two consecutive upward antidiagonals in the table:
1, 2, 6, 7, 15, ...
5, 3, 12, 10, 23, ...
4, 9, 13, 18, 26, ...
14, 8, 25, 19, 40, ...
11, 20, 24, 33, 41, ...
...
Subtracting (n-1)*(2*n-3) from each term in row n produces a permutation of numbers from 1 to 4*n-3:
1;
4, 1, 3, 2, 5;
8, 3, 6, 1, 5, 2, 7, 4, 9;
MATHEMATICA
P[n_, k_]:=Module[{m=2*n-1}, If[k<m, If[OddQ[k], -k+2m-1, m-k], If[OddQ[k], k, k-m+1]]]
Nmax=3; Flatten[Table[P[n, k]+(n-1)*(2*n-3), {n, 1, Nmax}, {k, 1, 4 n-3}]]
CROSSREFS
KEYWORD
nonn,tabf
AUTHOR
Boris Putievskiy, Jan 17 2025
STATUS
approved