OFFSET
2,1
COMMENTS
For n <= 10^5, a(n) < n^2, thus a(n) = k*n + (n-k) for some k, 1 <= k < n. Is this true for all n?
LINKS
Robert Israel, Table of n, a(n) for n = 2..10000
EXAMPLE
a(5) = 13 because the prime 13 = 23_5 with 2 + 3 = 5, and no smaller prime works.
MAPLE
f:= proc(n) local k, v, x;
for k from 1 do
v:= convert(convert(k, base, n), `+`);
if v > n then next fi;
x:= n*k+(n-v);
if isprime(x) then return x fi
od
end proc:
map(f, [$2..100]);
MATHEMATICA
a[n_]:=Module[{k=1}, While[DigitSum[Prime[k], n]!=n, k++]; Prime[k]]; Array[a, 67, 2] (* Stefano Spezia, Jan 04 2025 *)
CROSSREFS
KEYWORD
AUTHOR
Robert Israel, Dec 31 2024
STATUS
approved
