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A378481
Integers k such that A378414(k) == k (mod A066417(k)).
0
33, 77, 153, 372, 1540, 2300, 2692, 2736, 7812, 8721, 12593, 26025, 26481, 27972, 39321, 64009, 104409, 175441, 325180, 335616, 422593, 455625, 564376, 575040, 756460, 800073, 1104521, 2180545, 2304332, 3502665, 3691968, 5130909, 5515121, 9331441, 9546265
OFFSET
1,1
COMMENTS
Also integers k such that A000217(k) == k (mod A066417(k)).
So far, only 33 belongs both to A232538 and A378414.
EXAMPLE
Antidivisors of 77 are 2, 3, 5, 9, 14, 17, 22, 31, 51 and their sum is 154.
Then 77*78/2 mod 154 = 3003 mod 154 = 77.
MAPLE
with(numtheory): P:=proc(q) local j, k, n, v; v:=[];
for n from 3 to q do k:=0; j:=n; while j mod 2<>1 do k:=k+1; j:=j/2; od;
if n*(n+1)/2 mod (sigma(2*n+1)+sigma(2*n-1)+sigma(n/2^k)*2^(k+1)-6*n-2)=n
then v:=[op(v), n]; fi; od; op(v); end: P(10^5);
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Paolo P. Lava, Nov 28 2024
STATUS
approved