|
%I #9 Aug 13 2024 16:26:12
%S 1,-2,1,1,-2,1,0,2,-3,1,0,-2,4,-3,1,0,2,-4,5,-4,1,0,-2,4,-7,8,-4,1,0,
%T 3,-6,12,-15,10,-5,1,0,-6,12,-23,28,-20,13,-5,1,0,13,-26,48,-57,42,
%U -31,16,-6,1,0,-30,60,-110,130,-98,76,-43,20,-6,1
%N Triangle read by rows: The matrix inverse of the row reversed Euler table A026820.
%e Triangle starts:
%e [1] [ 1]
%e [2] [-2, 1]
%e [3] [ 1, -2, 1]
%e [4] [ 0, 2, -3, 1]
%e [5] [ 0, -2, 4, -3, 1]
%e [6] [ 0, 2, -4, 5, -4, 1]
%e [7] [ 0, -2, 4, -7, 8, -4, 1]
%e [8] [ 0, 3, -6, 12, -15, 10, -5, 1]
%e [9] [ 0, -6, 12, -23, 28, -20, 13, -5, 1]
%p with(LinearAlgebra):
%p A058400 := Matrix(10, (n, k) -> ifelse(k <= n, A026820(n, n - k + 1), 0)):
%p MatrixInverse(A058400);
%Y Cf. A026820, A008284, A058400, A375382 (row sums of abs(term)).
%K sign,tabl,new
%O 1,2
%A _Peter Luschny_, Aug 13 2024
|
