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A373307
Binary digits of Pi selected by stepping forward d+1 places at digit d, i.e., by skipping the next d places.
1
1, 0, 0, 1, 0, 1, 0, 0, 0, 1, 1, 1, 0, 1, 0, 1, 1, 1, 0, 0, 1, 0, 0, 1, 0, 0, 0, 1, 1, 0, 1, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1, 0, 0, 1, 0, 0, 0, 1, 1, 0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 1, 0, 1, 1, 0, 0, 0, 0, 1, 1, 0, 1, 0, 1, 0, 0, 1, 0, 1, 1, 0, 1, 0, 0, 0
OFFSET
1,1
COMMENTS
Are the digits uniformly distributed? Are all digit sequences uniformly distributed?
FORMULA
a(n) = the (n+a(1)+a(2)+...+a(n-1))-th digit in the binary expansion of Pi.
EXAMPLE
The sequence starts with the first digit of the binary expansion of Pi, which is 1. The next term is the digit 1+1 places after this, namely, 0, and so on.
The digits selected from Pi begin
Pi=1, 1, 0, 0, 1, 0, 0, 1, 0, 0, 0, 0, 1, 1, 1, ...
^ ^ ^ ^ ^ ^ ^ ^ ^ ^ ^
MATHEMATICA
a={1}; s=1; For[n=2, n<=100, n++, s+=Part[a, n-1]+1; digits=First[RealDigits[Pi, 2, s]]; AppendTo[a, Part[digits, s]]]; a
CROSSREFS
Cf. A004601.
Sequence in context: A352569 A101266 A260552 * A244612 A262805 A213728
KEYWORD
nonn,base
AUTHOR
Karl Levy, May 31 2024
STATUS
approved